2.33 of copper 2 oxide were burned in excess hydrogen gas. What mass of h20 was produced?
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CuO doesn't "burn" in H2 gas, it is reduced, which is the opposite of burning:
CuO + H2 → Cu + H2O
Supposing the missing units to be grams:
(2.33 g CuO) / (79.5457 g CuO/mol) x (1/1) x (18.01532 g H2O/mol) =
0.528 g (or whatever units were used to specify the mass of CuO originally) of H20
CuO + H2 → Cu + H2O
Supposing the missing units to be grams:
(2.33 g CuO) / (79.5457 g CuO/mol) x (1/1) x (18.01532 g H2O/mol) =
0.528 g (or whatever units were used to specify the mass of CuO originally) of H20