What volume of 0.600 M potassium chloride will contain 15.3 g of potassium chloride

Please show work if possible! Thank you for your help

This is a "molarity" problem, so we can use the following equation:
molarity KCl = (moles KCl) / (Liters of solution)
or
Liters of solution = (moles KCl) / (molarity)
Since we know "molarity of the KCl solution, we need to calculate the "moles KCl", before finding the number of Liters of this solution.
To find the number of moles of KCl, we need to divide its mass by its mole mass:
moles KCl = (mass KCl) / (mole mass KCl)
moles KCl = (15.3 g) / (74.551 g/mol)
moles KCl = 0.205212 mol
Liters of solution = (0.205212 mol) / (0.600 M)
Liters of solutiion = 0.34220201 L or 0.342 L rounded to three significant figures
Answer: About 0.342 L of 0.600 M potassium chloride solution will contain 15.3 g of potassium chloride.