Best answer: 2+sq root of 3x+4=6... Helllpp

If I got your question, you're looking to find x in:
2 + √3x+4 = 6

Subtract 2 from both sides, we get:
√3x+4 = 4

Square both side, the square and square root on the left cancel, and 4 squared is 16:
3x + 4 = 16

Subtract 4 on both sides:
3x = 12

Divide both sides by 3:
x = 4.

Subtract 2 from both sides:

√(3x + 4) = 4

Square both sides to cancel off the square root:

3x + 4 = 16

Subtract 4 from both sides:

3x = 12

Divide both sides by 3:

x = 4