Fe + O₂ → Fe₂O₃
Al + CuSO₄ → Al₂(SO₄)₃ + Cu
Mg(OH)₂ + HCl → MgCl₂ + H₂O
i have a really bad headache and so much stress please help me if your a genius
Al + CuSO₄ → Al₂(SO₄)₃ + Cu
Mg(OH)₂ + HCl → MgCl₂ + H₂O
i have a really bad headache and so much stress please help me if your a genius
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Hi again :P
In my earlier answer, I forgot to mention that I am also active in the chemistry section, as well as the math section.
Balancing chemical equations are like doing puzzles. The key to balancing equations is to make the reactant and the product side have equal numbers of each element. This key is also called the "law of conservation of mass".
To balance equations, you can only add coefficients. You cannot change the subscripts of the chemicals because that would change the formula of the chemical completely, and you won't have the same chemical anymore.
Having said that, the answers are:
1) Fe + O₂ → Fe₂O₃
4 Fe + 3 O₂ → 2 Fe₂O₃
Notice here that I added a 4 in front of the Fe, and a 2 in front of the Fe₂O₃. By doing this, I have 4 Fe atoms in the reactant side, and 4 Fe in the product side, because 2*2=4. If you notice in the Fe₂O₃, there is a subscript of 2 following Fe. This means that there already is 2 Fe atoms present in that compound. Thus, by adding a 2 in front of the Fe₂O₃, there are now 4 Fe atoms. But, adding a 2 in front of Fe₂O₃ also changes the number of oxygen atoms. Before I added the 2, there was a subscript of 3 following O. This means that there are 3 oxygen atoms already present. Thus, by adding writing a 2 in front of Fe₂O₃, there are now a total of 6 oxygen atoms because 2*3 = 6. The problem now is that there is 6 oxygen atoms in the product side, but only 2 oxygen atoms in the reactant side (i.e. there is only 2 oxygen atoms present in O₂). So, to compensate for this imbalance, I added a 3 in front of O₂, which means that there is now 3*2=6 oxygen atoms in the reactant side as well.
The other problems are done in pretty much the same fashion. Just remember to use the law of conservation of mass when balancing equations.
2) Al + CuSO₄ → Al₂(SO₄)₃ + Cu
2 Al + 3 CuSO₄ → Al₂(SO₄)₃ + 3 Cu
3) Mg(OH)₂ + HCl → MgCl₂ + H₂O
Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
In my earlier answer, I forgot to mention that I am also active in the chemistry section, as well as the math section.
Balancing chemical equations are like doing puzzles. The key to balancing equations is to make the reactant and the product side have equal numbers of each element. This key is also called the "law of conservation of mass".
To balance equations, you can only add coefficients. You cannot change the subscripts of the chemicals because that would change the formula of the chemical completely, and you won't have the same chemical anymore.
Having said that, the answers are:
1) Fe + O₂ → Fe₂O₃
4 Fe + 3 O₂ → 2 Fe₂O₃
Notice here that I added a 4 in front of the Fe, and a 2 in front of the Fe₂O₃. By doing this, I have 4 Fe atoms in the reactant side, and 4 Fe in the product side, because 2*2=4. If you notice in the Fe₂O₃, there is a subscript of 2 following Fe. This means that there already is 2 Fe atoms present in that compound. Thus, by adding a 2 in front of the Fe₂O₃, there are now 4 Fe atoms. But, adding a 2 in front of Fe₂O₃ also changes the number of oxygen atoms. Before I added the 2, there was a subscript of 3 following O. This means that there are 3 oxygen atoms already present. Thus, by adding writing a 2 in front of Fe₂O₃, there are now a total of 6 oxygen atoms because 2*3 = 6. The problem now is that there is 6 oxygen atoms in the product side, but only 2 oxygen atoms in the reactant side (i.e. there is only 2 oxygen atoms present in O₂). So, to compensate for this imbalance, I added a 3 in front of O₂, which means that there is now 3*2=6 oxygen atoms in the reactant side as well.
The other problems are done in pretty much the same fashion. Just remember to use the law of conservation of mass when balancing equations.
2) Al + CuSO₄ → Al₂(SO₄)₃ + Cu
2 Al + 3 CuSO₄ → Al₂(SO₄)₃ + 3 Cu
3) Mg(OH)₂ + HCl → MgCl₂ + H₂O
Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
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4Fe + 3O2 ------> 2Fe2O3
2Al + 3CuSO4 ---------> Al2(SO4)3 + 3Cu
Mg(OH)2 + 2HCL ---------> MgCl2 + 2H2O
2Al + 3CuSO4 ---------> Al2(SO4)3 + 3Cu
Mg(OH)2 + 2HCL ---------> MgCl2 + 2H2O