A mixture containing 0.80 mole of N2 and 0.35 mole of O2 was placed in a 1 liter vessel. Find the composition of the mixture at equilibrium at 3900C. Kc= 1.2E-2 at 3900C. N2(g)+O2(g)=2NO(g)
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...N2(g) + O2(g) <==> 2NO(g) ................ Kc= 1.2x10^-2 at 3900C
I 0.80M ..0.35M .............0
C...-x ......... -x .............+2x
E 0.8-x ...0.35-x ........... 2x
Kc = [NO]² / ([N2] [O2])
1.2x10^-2 = 4x² / (0.80-x) / (0.35-x)
x = 0.0127
[N2] = 0.77M
[O2] = 0.32M
[NO] = 0.055M
I 0.80M ..0.35M .............0
C...-x ......... -x .............+2x
E 0.8-x ...0.35-x ........... 2x
Kc = [NO]² / ([N2] [O2])
1.2x10^-2 = 4x² / (0.80-x) / (0.35-x)
x = 0.0127
[N2] = 0.77M
[O2] = 0.32M
[NO] = 0.055M