What is the theoretical yield

Butadiene Sulfone + Maleic Anhydride --------> 4-Cyclohexene-cis-1,2-Dicarboxylic Anhydride

C4H6O2S + C4H2O -----------------> C8H8O3

If you start with:
217.00 mg C4H6O2S
97.00 mg C4H2O

NOTE: The correct empirical formula for maleic anhydride is C4H2O3, not C4H2O

I'll do enough to get you stated and you can complete the problem yourself.

Formula weights:

C4H6O2S: 118.15 g/mol
C4H2O3: 98.06 g/mol

So we have

217.00 mg C4H6O2S => (217.00 mg)/(118.15 g/mol) = 1.837 mmol butadiene sulfone
97.00 mg C4H2O3 => (97.00 mg)/( 98.06 g/mol) = 0.9892 mmol maleic anhydride

Therefore, the limiting reactant is maleic anhydride.

The amount (moles) of product produced is:

moles of product = (moles of limiting reactant)*(moles product/moles reactant)


moles of product = (0.9892 mmol maleic anhydride)*(1 mole product/1 mole maleic anhydride)
moles of product = 0.9892 mmol

The remaining steps are:

(1) calculate the molecular weight of the product

(2) calculate the mass of product:

mass of product = (0.9892 mmol product)*(molecular weight of product)

This is the theoretical yield of the product based on the limiting reactant.