how many grams of copper (II) phosphate (molar mass = 380.5) can be made from 35.0 mL of 1.45 M sodium phosphate (molar mass = 164.0) and 25.0 mL of 0.830 M copper (II) chloride (molar mass = 134.5) ??
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2 Na3PO4 + 3 CuCl2 = Cu3(PO4)2 + 6 NaCl
moles of Na3PO4 = 1.45 Mole Liter ^-1 x .035 L = 0.05075 moles
these can react with 0.05075 x 3 /2 moles of CuCl2 = 0.07613 moles
we actually have .830 x .025 moles of CuCl2 = 0.02075 moles
so the Cu salt is used up first and is the limiting reagent
looking at the equation we see that
the moles of the copper phosphate formed = 0.02075 / 3 = 0.00692 moles
mass formed = 0.00692 x 380.5 = 2.632 g of copper (II) phosphate
moles of Na3PO4 = 1.45 Mole Liter ^-1 x .035 L = 0.05075 moles
these can react with 0.05075 x 3 /2 moles of CuCl2 = 0.07613 moles
we actually have .830 x .025 moles of CuCl2 = 0.02075 moles
so the Cu salt is used up first and is the limiting reagent
looking at the equation we see that
the moles of the copper phosphate formed = 0.02075 / 3 = 0.00692 moles
mass formed = 0.00692 x 380.5 = 2.632 g of copper (II) phosphate