Hey. Two plates are seperated by 80mm. The mean velocity is 22.4ms^-1. Q=V.A, and I believed A to be pi.r^2 right? But the answer to the question is 1.79m^3/s. What am i missing?
If it helps, I have been given a velocity distribution curve, which is a laminar velocity profile. Any help would really be appreciated, Thanks!!
If it helps, I have been given a velocity distribution curve, which is a laminar velocity profile. Any help would really be appreciated, Thanks!!
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Looks as though the plates have a width of 1 m, working back from the anwer you have given. Was that information supplied to you?
A=1.79/22.4 m^3
A=w x h
h=0.08
w= (1.79/22.4)/0.08=0.999 m
It is a rectangular duct, right? Not a circular pipe i.e. area is not pi.r^2 !
Laminar velocity profile means it is a parabola, but you have been given the mean, which seems sufficient to determine the correct answer; provided you know the plates are 1 m wide.
A=1.79/22.4 m^3
A=w x h
h=0.08
w= (1.79/22.4)/0.08=0.999 m
It is a rectangular duct, right? Not a circular pipe i.e. area is not pi.r^2 !
Laminar velocity profile means it is a parabola, but you have been given the mean, which seems sufficient to determine the correct answer; provided you know the plates are 1 m wide.