Peak voltage is 347V.
Instantaneous voltage is 208V.
I know the answer is 36.829 degrees, but I do not know how to get to that!
Below this table is the following:
E(inst)=E(max)*sin
E(max)=E(inst)/sin
sin
Can u help me with this??
Instantaneous voltage is 208V.
I know the answer is 36.829 degrees, but I do not know how to get to that!
Below this table is the following:
E(inst)=E(max)*sin
Can u help me with this??
-
(347V)*(sin theta) = 208V
Theta = arc sin 208/347 = 36 .829 degrees
Theta = arc sin 208/347 = 36 .829 degrees
-
is there more information?
to find the degree of an AC signal you normally need some sort of impedance or resistance number
or just hook an oscilloscope to whatever it is you're trying to figure out?
at any rate if thats wrong use the sine wave triangle where you have impedance, resistance, and reactance, and put theta in phi on the inside and figure it out from there, if I had your complete question I could answer it this is not enough.
to find the degree of an AC signal you normally need some sort of impedance or resistance number
or just hook an oscilloscope to whatever it is you're trying to figure out?
at any rate if thats wrong use the sine wave triangle where you have impedance, resistance, and reactance, and put theta in phi on the inside and figure it out from there, if I had your complete question I could answer it this is not enough.