Manometer question? Please help..exam tomorrow

I don't understand part A. How would I go about finding which fluid is which in the manometer?
I understand how to find the pressure afterwards...

Thanks a lot!

http://imageshack.us/f/152/screenshot201…

The fluid with the lighter SG will be displaced by and will float on the heavier fluid.

The cream always rises (eventually).
If you mix oil (low SG), and water (higher SG), the oil rises.
I'd venture to suppose glycerin (higher SG) is at the bottom.

A guess at the solution:
1.260g/cc-.702g/cc= .558g/cc
.558g/cc×3.2cm = 1.7856g/cm^2
1.7856 ×10^-3kg/10×10^-3m^2 = .17856kg/m^2
.17856kg/m^2 × 9.81N/kg = 1.7517 Pa

Editted and corrected