Current passing through a resistor
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Current passing through a resistor

[From: ] [author: ] [Date: 13-03-03] [Hit: ]
So R = 12/7 ohms.The voltage drop across this combination is (A*12/7)/(C + 12/7) = (A*12/7)/19/7 = A*12/19..The current through D = Voltage drop/resistance = (A*12/19)/D = (3*12/19)/4 = 9/19 Amperes-V=IR, where V= voltage, I= current,......
http://scioly.org/wiki/images/f/f3/Ichaelm%27s_Shock_Value_Test_2010.pdf
I'm having trouble with number 8. Can someone please give me an explanation?

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The parallel combination of C and D is given by 1/R = 1/3 + 1/4 = 7/12.
So R = 12/7 ohms.
The voltage drop across this combination is (A*12/7)/(C + 12/7) = (A*12/7)/19/7 = A*12/19..
The current through D = Voltage drop/resistance = (A*12/19)/D = (3*12/19)/4 = 9/19 Amperes

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V=IR, where V= voltage, I= current, and R= resistance. In this problem, you need to find the total current. you can do this by finding the total resistance of the circuit, using the voltage supplied by the problem, and solving for current. Once you do that, use I1/I2=R2/R1 to find the current for each resistor.

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