& 2. factor completely: 3ab(x + 1) − 2(x + 1)
thank you so much! i appreciate your help a lot! ♥
thank you so much! i appreciate your help a lot! ♥

Steps:
1. Factor like terms
2. Group the common factors and collect the remaining terms.
* * *
1. 10xy + 3y + 20ax + 6a
= y(10x + 3) + 2a(10x + 3)
= (y + 2a)(10x + 3)
2. Group x + 1 and collect the terms.
(3ab  2)(x + 1)
I hope this helps!
1. Factor like terms
2. Group the common factors and collect the remaining terms.
* * *
1. 10xy + 3y + 20ax + 6a
= y(10x + 3) + 2a(10x + 3)
= (y + 2a)(10x + 3)
2. Group x + 1 and collect the terms.
(3ab  2)(x + 1)
I hope this helps!

10xy + 3y + 20ax + 6a
y*(10*x + 3) + 2*a*(10*x + 3)
10*x + 3 is common to both terms....
(y + 2*a)*(10*x + 3)
#######
3ab(x + 1) − 2(x + 1)
(x + 1) is common to both terms
(x + 1)*(3*a*b  2)
y*(10*x + 3) + 2*a*(10*x + 3)
10*x + 3 is common to both terms....
(y + 2*a)*(10*x + 3)
#######
3ab(x + 1) − 2(x + 1)
(x + 1) is common to both terms
(x + 1)*(3*a*b  2)

y(10x + 3) + 2a(10x + 3)
(y + 2a)(10x + 3)
(3ab  2)(x + 1)
(y + 2a)(10x + 3)
(3ab  2)(x + 1)

Y(10x+3)+2a(10x+3)=(10x+3)(y+2a)