What is 4x^2 - 3 = x

ya, all i want is a logical answer and the steps you made to get that answer. I don't want any word answers like, 'u suck' or anything like that!
This is a quadratic equation, so I would have to use zero product property right? And subtract that x to make it equal zero, correct?

4x^2 - 3 = x

set equal to zero

4x^2 - x - 3 = 0

factor

4x^2 - 4x + 3x - 3 = 0

4x(x - 1) + 3(x - 1) = 0

(x - 1)(4x + 3) = 0

x = 1 or x = - 3/4

check in the original equation.

practice.

You are right, subtract x first and set equal to zero.
4x^2-x-3=0
Now put in quadratic formula where a=4, b=-1, c=-3
-(-1) +/-sqrt ((-1)^2-4(4)(-3))/(2(4))
1+/-sqrt (1+48)/(8)
1+/-sqrt (49)/(8)
(1+/-7)/(8)
(1+7)/8 and (1-7)/8
8/8 and -6/8
1 and -3/4

4x^2 - 3 = x
4x^2 - x - 3 = 0
4x^2 - 4x + 3x - 3 = 0
4x(x - 1) + 3(x - 1) = 0
(x - 1)(4x + 3) = 0
x = 1
x = -3/4

Your two roots/zeros/x-intercepts are 1, and -3/4.

(-4x -3) (-x+1)

the equation needed to solve is
4x^2 -x -3 = 0
use splitting the middle term :)

u suck a monley could do that