Can anyone differentiate this
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Can anyone differentiate this

[From: ] [author: ] [Date: 11-05-11] [Hit: ]
then the DE should be y - 2y + 2y = 0.Use the product rule.and y = e^x (sin x + cos x) + e^x (cos x - sin x) = 2 e^x cos x.Therefore,= 0.I hope this helps!......
y=e^xsinx show that d^2y/dx^2+2(dy/dx)+2y=0
thanks!! please do it in steps :)

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If y = e^x sin x, then the DE should be y'' - 2y' + 2y = 0.

Use the product rule.
y' = e^x sin x + e^x cos x = e^x (sin x + cos x)
and y'' = e^x (sin x + cos x) + e^x (cos x - sin x) = 2 e^x cos x.

Therefore, y'' - 2y' + 2y
= 2 e^x cos x - 2(e^x (sin x + cos x)) + 2(e^x sin x)
= 0.

I hope this helps!
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