Algebra Help!!! ASAP!

Help please. Please show work. I need this. Answer what you can, I'll give the winner 30 points. I will do that by opening up a question 2 more times and giving you best answer. I just really need this help.

square root (x + 10)-7=-5
4(3-x)^4/3-5=59
square root 36g^6
^3 square root 9/ ^3 square root 11
^3 square root (128x^13y^6)

Problem One
==========
sqrt(x + 10) - 7 = 5 Add 7
sqrt(x + 10) = 12 Square both sides
x + 10 = 12^2 = 144 subtract 10
x = 144 - 10 = 134

Check
- - - - -
sqrt(134 + 10) -7
sqrt(144) -7
12 - 7
5

Question Two
==========
sqrt(36 g^6)
sqrt(6 * 6 * g * g * g * g *g *g) Take out 1 of the 6's and 3 of the g's. there's nothing under the root sign.
6 * g * g * g = 6g^3

Question Three
===========
This one is a little hard to read.
sqrt(9) = 3
3^3 = 27

(sqrt(11) )^3
sqrt(11 * 11 * 11)
11*sqrt(11)

27/ (11 sqrt(11) Multiply top and bottom by sqrt(11)
27 sqrt(11)/11* sqrt(11) * sqrt(11)
27 sqrt(11) / 11*11
27 sqrt(11)/121

Problem Four
==========
sqrt(128) = sqrt(2 * 2 * 2 * 2 * 2 * 2 * 2) = 2^3 sqrt(2)
sqrt(x^13) = x^6 sqrt(x) Notice how the power divides by 2 and the remainder (1) goes under the root sign.
sqrt(y^6) = y^3

Now put it together
[8 sqrt(2)*x^6 sqrt(x) y^3 ] ^ 3

8^3 = 8 * 8 * 8 = 512
sqrt(2) ^3 = sqrt(2 * 2 * 2) = 2 sqrt(2)
512 * 2 sqrt(2) = 1024 * sqrt(2)

(x^3 sqrt(x) ) ^3 = x^9 sqrt(x * x * x) = x^10 sqrt(x)

(y^3)^3 = y^9. You multiply the powers. Now put it all together.

Now put the results together.
[1024 sqrt(2) * x^10* sqrt(x) * y^9]

I'd be content with 1 BA. The points don't matter. Honoring your word is.

square root (x + 10) - 7= -5 > square root (x + 10) = -5 + 7 > square root (x + 10) = 2 >
(x+10) = 4 > x = 4 - 10 > x = -6