4(3-x)^4/3-5=59 I am not sure how to interpret this problem. It could be one of these:
[4(3-x)^4]/(3-5) = 59 which yields: (3-x)^4 = -29.5 not very likely!
{[4(3-x)^4]/3}-5 = 59 which yields: (3-x) = (2)3^(1/4) again, not very likely!
[4(3-x)^(4/3)]-5 = 59 this gave a nice answer.
[4(3-x)^(4/3)]-5 = 59 > [(3-x)^(4/3)] = (59 + 5)/4 > (3-x)^(4/3) = 16 >
(3-x) = 16^(3/4) > 3-x = 8 > -x = 8-3 > -x = 5 > x = -5
square root 36g^6 > 6g^3
^3 square root 9/ ^3 square root 11 I'm not sure what ^3 at the beginning means. Perhaps this?:
[9^(1/2)/11^(1/2)]^3 > [3/11^(1/2)]^3 > 27/[(11)11^(1/2)]
^3 square root (128x^13y^6) If I interpret this the same way, then it is:
[(128x^13y^6)^(1/2)]^3 > [(2^7x^13y^6)^(1/2)]^3 > [8x^6y^3(2x)^(1/2)]^3 >
(512x^18y^9)(2x)^(3/2) > 1024x^19y^9(2x)^(1/2)
I hope this helps