Solve the following equations: Sin2x = Cosx , 0 <= x <= π
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Solve the following equations: Sin2x = Cosx , 0 <= x <= π

[From: ] [author: ] [Date: 11-05-17] [Hit: ]
524, 2.......
1) Sin2x = Cosx , 0 <= x <= π

2) tan 2x = 0 , -2 π <= x <= π

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1) sin2x is equal to 2sinxcosx.
So: 2sinxcosx=cosx
Divide both sides by cos x and you have: 2sinx=1
Rearrange to find x: sinx=1/2
So: x = 0.524 radians

Find other answers using the Sine graph. The other positive answer is π - 0.524 = 2.16 radians

So x = 0.524, 2.16
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