The problem is -1x^5-5x^4-1x^3-9x^2-9x-0
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The real zeros are:
x = 0
x = -5.08307062
x = -0.81919114
and also
x = 0.451131027 +/- 1.3992354976 i
How to find them? First of all, you can factor out the x term, to get
x ( x^4 + 5x^3 +x^2 +9x + 9) = 0
That gives x = 0 as a root, and leave us with a 4th order polynomial. There are ways to find the exact solution of this, but they involve multiple cube roots and square roots. I think computer methods are generally better.
x = 0
x = -5.08307062
x = -0.81919114
and also
x = 0.451131027 +/- 1.3992354976 i
How to find them? First of all, you can factor out the x term, to get
x ( x^4 + 5x^3 +x^2 +9x + 9) = 0
That gives x = 0 as a root, and leave us with a 4th order polynomial. There are ways to find the exact solution of this, but they involve multiple cube roots and square roots. I think computer methods are generally better.