How do you integrate(x^2/sqr(4-x^2)

∫x²/√(4 - x²) dx

x = 2*sin(t)

dx = 2*cos(t) dt

∫(4*sin²(t))(2*cos(t) dt)/2*cos(t)

2*∫(1 - cos(2t)) dt

2[t - sin(t)*cos(t)] + C

2t - 2*sin(t)*cos(t) +C

2*arcsin(x/2) - 2*(x/2)(√(4 - x²))/2 + C

= 2*arcsin(x/2) - x√(4 - x²)/2 + C