I don't understand how to do the difference of cubes thing. And please don't direct me to another website such as purplemath, I've tried reading it, yet don't understand. Please help!
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(a-b) (a^2 + ab + b^2) is your dif of cubes formula.
A= 3x^2
B= y^3
(you're taking the 3rd root of both 27x^6 and y^6)
Then just input A and B into the formula.
(3x^2-y^3)(9x^4 + 3x^2y^3 +y^6)
Done.
A= 3x^2
B= y^3
(you're taking the 3rd root of both 27x^6 and y^6)
Then just input A and B into the formula.
(3x^2-y^3)(9x^4 + 3x^2y^3 +y^6)
Done.
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ok lestat, any difference of two cubes
a^3 - b^3 = (a - b) (a^2 + ab + b^2)
in your problem, the "a" is the cube root of 27 x^6 which is 3x^2
the "b" is the cube root of y^9 which is y^3
so the factors are (3 x^2 - y^3) (9 x^4 + 3 x^2 y^3 + y^6)
hope that helps, but if you are still confused, hit me up: loyalfriend001@yahoo.com
sam
a^3 - b^3 = (a - b) (a^2 + ab + b^2)
in your problem, the "a" is the cube root of 27 x^6 which is 3x^2
the "b" is the cube root of y^9 which is y^3
so the factors are (3 x^2 - y^3) (9 x^4 + 3 x^2 y^3 + y^6)
hope that helps, but if you are still confused, hit me up: loyalfriend001@yahoo.com
sam