Evaluate the Integral..who can do this

integral of tan(26x) sec^2(26x) dx =?

Can someone show the work pls...

∫tan(26x)sec²(26x)dx

since we know that
d/dx(tanx) = sec²x, we can use that relationship to solve this:

let u = tan(26x)
du = 26sec²(26x)dx

∫u(du/26)
= ∫(1/26)udu
= (1/52)u² + C
= (1/52)tan²(26x) + C

Hope this helps :D