Using elimination to solve each system of equations
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Using elimination to solve each system of equations

[From: ] [author: ] [Date: 11-10-04] [Hit: ]
which is 18.Therefore,......
How to write an equation out of this :

The sum of two numbers is 24.Five times the first number minus the second number is 12.What are the two numbers ?

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let the two numbers be: x and y

x + y = 24

5x - y = 12

add the two equations...

6x = 36
x = 6

y = 18

check


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Ok, let's start by assigning each number a variable. Let's call the first number x and the second number 24-x. The question gives you a math problem to help solve your question, which is five times the first number minus the second number is 12. Therefore, we just input our variables into the equation and solve.

5(x)-(24-x)=12
Break open the brackets
5x-24+x=12
Clean up the Equation
6x=36
x=6

Now just do 24-6 to get the other number, which is 18.
Therefore, the two numbers are 6 and 18

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Let's be x and y the numbers:
x + y = 24
5x - y = 12
by elimination

adding both equations (x + 5x) (y - y) and (24 + 12) gives

6x + 0y = 36

6x = 36
x = 36/6 = 6

From the first equation x + y = 24

(6) + y = 24
y = 24 - 6
y = 18

Your numbers are 6 and 18
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