Solve this simple first order differential equation

dy/dx + 2y =8
This is straight forward and driving me crazy. Please include detail. Thanks

dy/dx = 8 - 2y
dy/dx = -2 (y - 4)
1/(y-4) dy = -2 dx

Integrate both sides:
∫ 1/(y-4) dy = ∫ -2 dx
ln|y-4| = -2x + C₀
y - 4 = e^(-2x)*e^(C₀)
y - 4 = C e^(-2x)

y = C e^(-2x) + 4


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