(2x+3)(x-1)(x+2)-x^2(1-x), please explain in steps how to answer this question

Am I supposed to be timesing all 3 brackets at the same time? Cos when I just times just the first two brackets and then times that with the next bracket, I keep getting the wrong answer?

please explain, thank you

Multiply the brackets a pair at a time. For example, you could start here:

(2x+3)(x-1) = 2x² + x - 3,

then bring in the (x + 2):

(2x² + x - 3)(x + 2) = 2x³ + 5x² - x - 6,

then deal with the terms at the end, -x²(1-x), which need to be added on to the above:

-x²(1-x) = -x² + x³.

Add these all up and you get:

(2x+3)(x-1)(x+2)-x²(1-x) = 2x³ + 5x² - x - 6 - x² + x³

which simplifies to

3x³ + 4x² - x - 6.

And, just to verify that this is correct:

http://www.wolframalpha.com/input/?i=%28…

your doing it right

Use Distributive Prop. once on the first two [(2x+3)(x-1)]then on your result[(2x^2-2x+3x-3) or (2x^2+x-3) and the third term (x+2)

(2x+3)(x-1)(x+2)-x^2(1-x)

2x times x, 2x times -1, 3 times x, 3 times -1

(2x^2-2x+3x-3)(x+2)-x^2(1-x)

-2x+3x=x, -x^2times1, -x^2times-x

(2x^2+x-3)(x+2)-x^2+x^3

2x^2timesx, 2x^2times2, xtimesx, xtimes2, -3timesx, -3times2

2x^3+4x^2+x^2+2x-3x-6-x^2+x^3

2x^3+x^3=3x^3, 4x^2+x^2-x^2=4x^2, 2x-3x=-x, -6

Your Answer:
3x^3+4x^2-x-6

Essentially you would expand the equation then simplify.

(2x+3)(x-1)

then

(x+2)-x^2

Group all your Like Terms, and you're good to go.

Do the first 2 brackets,and you will have:(2x^2+x-3)(x+2)-x^2+x^3.Then do the remaining brackets.4x^3+4x^2+x-6=4x^2(x+1)+x-6

(2x+3)(x-1)=2x²+x-3
(2x²+x-3)(x+2)=2x³+5x²-x-6

x²(1-x)=x²-x³

2x³+5x²-x-6-x²-x³=x³+4x²-x-6

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