So we just started the chapter of volume and surface area in high school (1st year) so I dont consider myself an expert on it but a question which i need your help today is as follows :
A rectangular pyramid of height 40 cm with a square base of sides 30cm each is put into a cubical tank of sides 40 cm each.The tank is then filled with water.If the pyramid is removed find the DEPTH of water in the tank.No diagram provided.
The answer with the most accurate detail will be given best answer...please guys I need it soon!
Thanks!
Rose
A rectangular pyramid of height 40 cm with a square base of sides 30cm each is put into a cubical tank of sides 40 cm each.The tank is then filled with water.If the pyramid is removed find the DEPTH of water in the tank.No diagram provided.
The answer with the most accurate detail will be given best answer...please guys I need it soon!
Thanks!
Rose
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Volume of cube = (40)^3 cm^3 = 64000 cm^3
Volume of pyramid = (1/3)(area of base)(height) = (1/3)(30^2)(40) = 12000 cm^3
when the pyramid is removed, the remaining volume is: 52000 cm^3
the area of the base of the cube = 1600 cm^2
the height of the remaining water in the tank is: 52000/1600 = 32.5 cm
qed
Volume of pyramid = (1/3)(area of base)(height) = (1/3)(30^2)(40) = 12000 cm^3
when the pyramid is removed, the remaining volume is: 52000 cm^3
the area of the base of the cube = 1600 cm^2
the height of the remaining water in the tank is: 52000/1600 = 32.5 cm
qed
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volume of pyramid=30x30x40=36000cm^3
volume of tank=40x40x40=64000cm^3
After removing the pyr. water volum is 64000-36000=28000cm^3
to find dept 28000/(40x40)=17.5cm
volume of tank=40x40x40=64000cm^3
After removing the pyr. water volum is 64000-36000=28000cm^3
to find dept 28000/(40x40)=17.5cm