Collect all terms in one side,
x^2 + x - 2 = (x+2)(x-1) = 0
x = -2, 1
x^2 + x - 2 = (x+2)(x-1) = 0
x = -2, 1
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2 - x^2 = x
-x^2 - x + 2 = 0 (Multiply by -1)
x^2 + x - 2 = 0 (Factor this or use quadratic formula.)
(x+2)(x-1)=0
x = -2 or x = 1
Hope that helped.
-x^2 - x + 2 = 0 (Multiply by -1)
x^2 + x - 2 = 0 (Factor this or use quadratic formula.)
(x+2)(x-1)=0
x = -2 or x = 1
Hope that helped.
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you have to use the quadratic thing.
so change the problem to:
-1(x^2 + x + 2) = 0
-1 (x-1) (x+2) =0
Then x= 2 answers, forget the -1
so change the problem to:
-1(x^2 + x + 2) = 0
-1 (x-1) (x+2) =0
Then x= 2 answers, forget the -1
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2-x^2 = x
2-x^2-x = 0
-x^2-x+2 = 0
-(x^2+x-2) = 0
x^2+x-2 = 0/-1
x^2+x-2 = 0
(x+2)(x-1) = 0
(x+2)=0 or (x-1)=0
x+2 = 0
x = 0-2
x = -2
x-1 = 0
x = 0+1
x = 1
x=-2 or x=1
2-x^2-x = 0
-x^2-x+2 = 0
-(x^2+x-2) = 0
x^2+x-2 = 0/-1
x^2+x-2 = 0
(x+2)(x-1) = 0
(x+2)=0 or (x-1)=0
x+2 = 0
x = 0-2
x = -2
x-1 = 0
x = 0+1
x = 1
x=-2 or x=1
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solve for x in 2 - x^2 = x ?
x^2 + x - 2 = 0
(x + 2)(x - 1) = 0
x = - 2 or x = 1
check
¶
x^2 + x - 2 = 0
(x + 2)(x - 1) = 0
x = - 2 or x = 1
check
¶
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2-x^2=x
0=x^2+x-2
0=(x-1)(x+2)
x=1,-2
0=x^2+x-2
0=(x-1)(x+2)
x=1,-2