Evaluate a2 - b +2c if a = 5, b = 17, and c = 2.

ok, this is: a(squared) - b+2c
a=5
b=17
c=2

so i plugged in ... idid 5 times 5... 25
25 minus 17 + 2(2)
igot... 25-17+4
then, 25- 21
... igot 4


but the problem is .... that wasnt a choice:/
These are the choices:
-15
12
22

Did ido something wrong????? HELP ME!!!!


Thanx!

yes you did do something wrong, its not order of operations. You messed up on the last step on the part where you got 25-17+4. instead of adding 17 & 4, you do 25-17 first because its left to rite therefore leaving it 8+4 which equals 12 so the answer 12

a+5
b+17
c+2

5^2-17+2^2
^ -->25 ^ -->4
25-17+4 or 25+ -17+4

25-17=8
8+4=12

Therefore, your answer is 12. Your welcome!

25 - 17 + 4 = 12

You're subtracting (17 + 4) instead of subtracting 17 and adding 4. Subtract 17 from 25, then add 4.

You just flipped a sign.

25-17+4 = 12.

a^2 - b + 2c = z

5^2 - 17 + 2 * 2 = z

25 - 17 + 4 = z

12 = z


where you went wrong
25 - 17 + 4
8 + 4
12

or
25 - 13
12

5x5 - 17 + 2x2
25 - 17+ 4
25 + 4 - 17
29 -17 = 12

answer is 12

25-17+2(2)
25-17=8
8+4=12

25 - 17 + 4
= 29 - 17 = 12

u do the 5 squared first and get 25

25-17 and u get 8

8 + 4 and you get 12.

first i got 4 to. but if u combine 4 & 25 u get 29. then subtract 17 and get 12. so 12 is the right answer