Please help i am confused about this...f(x)+g(x)/h(x) when Given f(x)=2x/x-3 g(x)= -1/x h(x)=x+2/x

please show work. Thank you

Given f(x)=2x/x-3 g(x)= -1/x h(x)=x+2/x

f(x)+g(x)/h(x)…answer 2x^2-x+3/(x-3)(x+2)

it's simple...

just substitute the variables of the functions in the equation

f(x)+g(x)/h(x) = 2x/x-3 + -1/x/(x+2)/x
=2x/(x-3) - 1/(x+2) the x's are cancelled out
=(2x(x+2))-1(x-3))/(x-3)(x+2) just cross multiply for the numerator and multiply the denominators
=(2x^2+4x - x +3)/(x-3)(x+2)
=(2x^2 + 3x + 3)/(x-3)(x+2)

your welcome....

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OK. I am assuming that it is [f(x)+g(x)]/h(x).
and that f(x) = x/(x-3), and h(x) = (x+2)/x.

So, [x/(x-3) -1/x]/(x+2)/x. Now the LCD of the numerator is x(x-3) so multiply all terms in the numerator by that to get (2x^2 -x+3)/(x(x-3)). Now divide by (x+2)/x and this is the same as multiplying by x/(x+2). When you do that the x's in the top and bottom cancel and you're left with
[2x^2-x+3]/[(x-3)(x+2)] which is your answer.