DIVIDING POLYNOMIALS HELP

4x³ + 6x ² - 22x - 12
_______________
2x + 6


That's 4x to the third and the number above the 6x is a 2. PLEASE WHAT'S THE ANSWER! I've been on this for hours! Literally!

4x³ + 6x ² - 22x - 12
_______________
2x + 6
= 2[2x^3+3x^2--11x-6]/[2(x+3)]

==[2x^3+3x^2--11x-6]/[(x+3)]
\

=[ 2x^3+6x^2--3x^2--9x--2x--6]/[x+3]

=2x^2-3x-2

4x³ + 6x ² - 22x - 12
_______________
2x + 6

=[2(2x³ + 3x ² -11x - 6)]/[2(x+3)]

=[2x³ + 3x ² -11x - 6]/[x+3]

=[2x^3+6x^2--3x^2--9x--2x--6]/[[x+3}

=[2x(x^2+3)-3x(x+3)-2(x+3)]/[x+3]

=[(x+3)(2x^2--3x--2)]/[x+3]

=2x^2--3x--2