Show that (cosecx*secx)/cotx=1+tan^2x

(cosecx*secx)/cotx=1+tan^2x

= [1/sinx*1/cosx]/[cosx/sinx]

= [1/(sinx*cosx)]/[cosx/sinx]

= [1/cosx]/cosx

= 1/cos^2x

= [sin^2x+cos^2x]/cos^2x

= sin^2x/cos^2x+ cos^2x/cos^2x

= tan^2x+1

Would it be acceptable? Thank You.

That's totally acceptable

Teehee..... secx....

Yes, that's good.