Math please help?!? 10 points to best answer

I do not understand exactly how to do these kinds of problems. Can someone please explain what I do to solve these problems? I don't understand things like this easily. Thank you

1. The measure of an acute angle is less than 90 degrees. If an acute angle measures 3x - 15, then the inequality to represent its measure is 3x - 15 < 90. Solve to find the measure of x.

x<25
x<35
x<45

2. Solve 3(x - 2) > 4(2x + 11)

t>-10
t>1.8
t<1.8
t<-10

3. Solve 8t + 16 > 16t - (12t - 20)

{t| t > 1}
{t| t > -1}
{t| t < 4}
{t| t > 4}

3x - 15 < 90
Add 15 to both sides:
3x < 105
Divide both sides by 3
x < 35


3(x - 2) > 4(2x + 11)
Expand.
3x - 6 > 8x + 44
Add 6 to both sides:
3x > 8x + 50
Minus 8x from both sides:
-5x > 50
Divide both sides by -5. When dividing or multiplying by a negative number, you must reverse the inequality sign.
x < 10


8t + 16 > 16t - (12t - 20)
8t + 16 > 4t + 20
Minus 4t from both sides and minus 16 from both sides
4t > 4
Divide both sides by 4
t > 1

Hope this helped :)

1)
3x-15<90
Adding 15 on both sides,
3x-15+15<105
3x<105
Dividing by 3 which is a positive quantity, inequality is preserved.
x<35
Option B

2)
3x-6>8x+44
Adding 6-8x to both sides,
-5x<50
Dividing by -5, a negative quantity, inequality is reversed
x>-10
Option A

3)
8t+16>16-12t+20
Adding 12t-16 on both sides
20t>20
Dividing by 20, a positive quantity, inequality is preserved
t>1
Option A

go to mathway.com and type just the equation in no word. promise youll get your answer dont put in the answer choices either but type it in just how you did