Prove that
1-1/√2+1/2-1/2√2+...=2-√2
1-1/√2+1/2-1/2√2+...=2-√2
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1-1/√2+1/2-1/2√2+...
= 1/(1 + 1/√2)
= √2/(√2 + 1)
= √2*(√2 - 1)
= 2-√2
QED
= 1/(1 + 1/√2)
= √2/(√2 + 1)
= √2*(√2 - 1)
= 2-√2
QED
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Jacky,
Thanks for picking my answer as the best.
For any infinite geometric series, sum = a(1)/(1-r), where a(1) is the first term, r is the common ratio.
Thanks for picking my answer as the best.
For any infinite geometric series, sum = a(1)/(1-r), where a(1) is the first term, r is the common ratio.
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