AB& CD are the two chords intersecting at point E in a circle of centre O prove that <AOC+<BOD=2<AEC
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AB& CD are the two chords intersecting at point E in a circle of centre O prove that <AOC+<BOD=2<AEC

[From: ] [author: ] [Date: 11-12-21] [Hit: ]
center O and E,3) Adding (i) & (ii),But from triangle ADE,Hence,......
Please important

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[Wish you have your sketch prepared for the question]

1) Consider, the points C, A & D which are on the circle whose center is O. Also the point E is on the chord DC.

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2) Similarly considering the points B, A, D, center O and E,


3) Adding (i) & (ii),


But from triangle ADE,
Hence,
1
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