In the nth row of Pascal's Triangle where the first row is n=0, the arithmetic mean of the elements is 51.2

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In the nth row of Pascal's Triangle where the first row is n=0, the arithmetic mean of the elements is 51.2

[From: ] [author: ] [Date: 11-12-26] [Hit: ]

2^n = 51.by inspection,......

Sorry, full question: In the nth row of Pascal's Triangle where the first row is n=0, the arithmetic mean of the elements is 51.2. What is the value of n?

Can anyone help with this Pascal's Triangle problem? Thanks so much!! :D

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sum of the nth row = 2^n, ie 2^0 = 1, 2^1 = 2, ... 2^9 = 512 etc
also note that the n th row has (n+1) #s in it
2^n = 51.2(n+1)
by inspection, n = 9 <-------

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