Trig q. Please help me out!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Trig q. Please help me out!

Trig q. Please help me out!

[From: ] [author: ] [Date: 11-12-29] [Hit: ]
a. 8.0 feet b. 0 feet c. 4.0 feet d.......
Jan observes a buoy bobbing up and down through a total amplitude of 8 feet. Beginning at the top of the wave, if the buoy completes a full cycle every 8 seconds, what is the height of the buoy relative to its lowest point after 12 seconds?

a. 8.0 feet
b. 0 feet
c. 4.0 feet
d. 12.0 feet

-
So the total amplitude is 8 feet. That means the buoy drops down 4 feet and then rises back to it's starting point for one full amplitude.

It takes 8 seconds for a full cycle, or 4 seconds down and 4 seconds back up.

Where is the buoy after 12 seconds?

4 seconds down + 4 seconds back up + 4 seconds down means it is now 4 feet down.

EDIT: Oops! I didn't read the whole problem. It says, "where is the height of the buoy relative to its LOWEST point...?"

That means it is b. 0 feet.

:)
1
keywords: out,Trig,help,Please,me,Trig q. Please help me out!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .