How to resolve this math problem

"Ana has 48 apples, and Jane has 36 apples. How many apples must Ana give to Jane, that they will have the same amount of apples?"

I know how to resolve it, using all of the operations, but this friend of mine, which is in primary school, hasn't learned yet the "x" and "/" operations. How can I resolve the problem, without using those operations?

"Ana has 48 apples, and Jane has 36 apples. How many apples must Ana give to Jane, that they will have the same amount of apples?"

I know how to resolve it, using all of the operations, but this friend of mine, which is in primary school, hasn't learned yet the "x" and "/" operations. How can I resolve the problem, without using those operations?

I am answering exactly what you have proposed. A situation where one is not familiar with multiplication of division.

It means one is familiar with Addition and substraction.

Ana = 48
Jane = 36

Difference : ana – jane = 48-36 =12
Since we are substracting jane from Ana, it means jane has more no of apples. So, Ana must give her apple to jane.

If ana given 1 then ana = 48-1 = 47 and jane = 36+1 = 37
If ana given 2 then ana = 48-2 = 46 and jane = 36+1 = 38
If ana given 3 then ana = 48-3 = 45 and jane = 36+1 = 39
If ana given 4 then ana = 48-4 = 44 and jane = 36+1 = 40
If ana given 5 then ana = 48-5 = 43 and jane = 36+1 = 41
If ana given 6 then ana = 48-6 = 42 and jane = 36+1 = 42

Here both has same no of apples.

So, ana must give 6 no of apples to jane in order to equate the no of apples.

You can impress your little friend. :)

This is simple one.

1) The difference of the two is 12. Dividing 12 by 2, it is = 6.
So Ana has to give 6 apples to Jane, so that Ana will have (48-6) = 42 and Jane will have (36+6) = 42 apples.

2) Alternatively you may try this also: