Probability! please help! 10 points!

Five years after 650 high school seniors graduated, 400 had college degree and 310 were married. Half of the students with a college degree were married. What is the probability that a student has college degree or is not married? Enter your answer in simplified fraction form; example: 33/51

400 with college degree of which 200 married, 200 unmarried
650-310 = 340 unmarried
P(college degree or unmarried) = P(college degree) + P(unmarried) - P(both)
= (400 + 340 - 200)/650 = 540/650
= 54/65
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Probability that a student has college degree = P(A) = 400/650
Probability that a student is NOT married = P(B) = (650-310) / 650 = 340/650
The events A and B are NOT MUTUALLY EXCLUSIVE
P(A and B) = (400*1/2) / 650 = 200/650
According to Addition Theorem of Probability, when the events are NOT mutually exclusive
Required probability = P(A or B) = P(A)+P(B)-P(A and B)
= 400/650+340/650-200/650
= 540/650
= 54/65

400 had college degrees and half of those were married, which means 200 were married. So of the 310 married students, 110 did not have a college degree and 200 did.



So 400 + 110 had a college degree or were married. 90 had no college degree and were not married.

400 + 90 had a college degree or were not married P = 490 / 600 = 49/60

200/650 i.e. 4/13

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