how do you integrate the function (x^3-x)/(x+1) dx ?
do you let u = x^3-x?
Any help is appreciated? thanks!
do you let u = x^3-x?
Any help is appreciated? thanks!
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(x^3-x) is divisible by x+1
Use synthetic division then integrate
Use synthetic division then integrate
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Wolfram alpha may be able to help, type in int((x^3-3)/(x+1),x)
it will tell you step by step
http://www.wolframalpha.com/
it will tell you step by step
http://www.wolframalpha.com/
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No, simplify it to x^2 - x