Quadratic Equation Math Question

(2x-1)/(x+5) = (x+2)/(x+3)

Simplify for x?

I tried simplifying the denominators, to get x^2 - 2x - 13

Then, I substituted that into the quadratic formula, but I've done something wrong. Possible answers are:

a) x = -2 plus/minus the square root of 14
b) x = -1 plus/minus the square root of 14
c) x = 2 plus/minus the square root of 14
d) x = 1 plus/minus the square root of 14

(2x-1)/(x+5) = (x+2)/(x+3)
(2x-1)(x+3) = (x+2)(x+5)
2x^2+6x-x-3 = x^2+5x+2x+10
2x^2+5x-3 = x^2+7x+10
2x^2+5x-3-x^2-7x-10 = 0
x^2-2x-13 = 0

x = -b+-√(b^2-4ac) / 2a
x = -(-2)+-√((-2)^2-4(1)(-13)) / 2(1)
x = 2+-√(4+52) / 2
x = 2+-√56 / 2
x = 2+-√4√14 / 2
x = 2+-2√14 / 2
x = 1+-√14

Answer: D