A math question, help please

A water treatment plant uses batch deliveries of two levels of chlorine concentrations to mix to create the level of concentration needed on any given day. Determine how many liters of a 3% chlorine solution and how many liters of a 5% chlorine solution should be mixed to produce 500 liters of a 4.4% chlorine solution.

This problem is like the one I had asked earlier I think. Yes, it's for homework, but I really don't know how to do this problem step by step. I keep messing up about half way through and keep ending up with the wrong answer. Help please??

You'll need to write two equations and relate them. One is for the mixture, the other is for total volume. Solve on in terms of the other, then substitute
Mixture:
(volume of solution 1 * percentage) + (volume of solution 2 * percentage) = total volume * desired percentage
Total volume:
volume of solution 1 + volume of solution 2 = total volume

Mixture
0.05x + 0.03y = 500 * 0.044
0.05x + 0.03y = 22


Total volume:
500 = x + y
Solve in terms of x or y, then substitute this into mixture equation
500 - y = x

Substitute:
0.05(500 - y) + 0.03y = 22
25 - 0.05y + 0.03y = 22
-0.05y + 0.03y = -3
-0.02y = -3
y = 150

Now you can plug in y in the total volume equation to find the volume of x:

500 = x + y
500 = x + 150
350 = x

Plug these two values into our original equation to check our work:

0.05x + 0.03y = 500 * 0.044
0.05(350) + 0.03(150) =? 22
17.5 + 4.5 =? 22
22 = 22

So we want 350 liters of the 5% solution and 150 liters of the 3% solution to get 500 liters of 4.4% solution.

why didn't you talk it with your classmate it will help a lot

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