What is D'(x) of D(x) = (300-2x)^(1/2)

explain how if you can, thanks

(300-2x)^(1/2)

You need to use chain rule for this.
(1/2)[(300-2x)^-(1/2)](-2)

D'(x) = -1 divided by the square root of (300-2x)

D(x) = 300^1/2 - 2x^1/2

D(x) = 10√3 - 2x^1/2

D'(x) = -x^(-1/2)