If a model rocket is launched with an initial velocity of 80 ft/sec from a height of 96 ft, then its height in feet "t" seconds after launched is a function defined by h(t) = =16t^2 + 80t +96
a. How long after launch will the model rocket hit the ground (assume the parachute fails)?
b. Why is the variable in the function notation h(t) a "t" ?
c. find the highest point in the trajectory of the model rocket
Please and thank you very much!
a. How long after launch will the model rocket hit the ground (assume the parachute fails)?
b. Why is the variable in the function notation h(t) a "t" ?
c. find the highest point in the trajectory of the model rocket
Please and thank you very much!
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h(t) = -16t² + 80t + 96
h(t)/-16 = t² - 5t - 6
h(t)/-16 = t² - 5t + 25/4 - 25/4 - 24/4 ..... [6 = 24/4]
h(t)/-16 = (t - 5/2)² - 49/4
h(t)/ = -16(t - 5/2)² + 196
a). It goes up for 5/2 sec & down for 5/2 sec - a total of 5 sec
b). t is for time, in seconds
c). 196 feet
h(t)/-16 = t² - 5t - 6
h(t)/-16 = t² - 5t + 25/4 - 25/4 - 24/4 ..... [6 = 24/4]
h(t)/-16 = (t - 5/2)² - 49/4
h(t)/ = -16(t - 5/2)² + 196
a). It goes up for 5/2 sec & down for 5/2 sec - a total of 5 sec
b). t is for time, in seconds
c). 196 feet