the question is: and i need to find an expression for x in terms of w.
e ^ (wx+2) / e^5 = 2
My answer is:
x = (w log e / 10 log e ) -2
I think this is right, but not sure.
e ^ (wx+2) / e^5 = 2
My answer is:
x = (w log e / 10 log e ) -2
I think this is right, but not sure.
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e ^ (wx+2) / e^5 = 2
e^ (wx +2 -5) = 2
e^ (wx -3) = 2
wx -3 = ln 2
wx = 3 + ln 2
x = (3 + ln 2) / w
e^ (wx +2 -5) = 2
e^ (wx -3) = 2
wx -3 = ln 2
wx = 3 + ln 2
x = (3 + ln 2) / w
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Take the natural log of both sides:
ln(e^(wx+2)/e^5) = ln2
ln(e^(wx+2)) - ln(e^5) = ln2
(wx+2)ln(e) - 5ln(e) = ln2
(wx+2) = 5 + ln2
x = (3+ln2)/w
ln(e^(wx+2)/e^5) = ln2
ln(e^(wx+2)) - ln(e^5) = ln2
(wx+2)ln(e) - 5ln(e) = ln2
(wx+2) = 5 + ln2
x = (3+ln2)/w
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Step 1 get rid of the e^5 by subtracting 5 from the top exponential using indices laws
e^(wx-3)=2
take tje log
log(2)=wx-3
log(2)+3=wx
x=(log(2)+3)/w
e^(wx-3)=2
take tje log
log(2)=wx-3
log(2)+3=wx
x=(log(2)+3)/w
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First, use natural logs for exponential functions: (wx+2)-5 equal ln2. Next, simplify left side of equation: wx-3 equal ln2. Now solve for w: (ln2+3)/x.