3x^2-9x+4=0 (1) Find the discriminant. (2)Find number of real solutions

9^2 - 4(3)(4) =
81 - 48 =
33
2

3x^2-9x+4=0

1) a=3,b=-9,c=4

D=b^2-4ac

=(-9)^2-(4*3*4)

=81-48=33

2)The discriminant is greater than zero then the equation has two different real solutions.

3x^2 - 9x + 4 = 0
Discriminant is b^2 - 4ac
81 - 4*3*4 = 33
So two real solutions
[9 +/- sqrt(33)]/6

Regards - Ian

The discriminant is the b^2 - 4ac term. Use 3 for a, -9 for b and 4 for c:

(-9)^2 - 4(3)(4) = 81 - 48 = 33

There are two real solutions.