Find the integral - Calculus

Find the integral of dx/sqrt(2-5x)

and the integral of dx/(x+3)

the 1st is equal to integral of (2-5x)^-1/2
u=2-5x
du=-5 dx
du/-5=dx

-1/5 integral u^-1/2

-1/5 *(1/1+(-1/2)) u^1/2
-1/5*(1/(1/2)u^1/2
-1/5*2*u^1/2
(-2/5)u^1/2
(-2/5)(2-5x)^1/2
-2/5 *sqrt(2-5x)


the 2nd is

dx/(x+3)
u=x+3
du=dx

du/u
ln u
ln(x+3)

1) use substitution u = 2 - 5x

2) u = x + 3