Simple Integral Problem........

Integrate Sinx * Cosx

Provide your answer in terms of Sine NOT Cosine.

Thanks!

∫sinx cosx dx = ∫sinx d(sinx) = ½ sin²x + C
OR
∫sinx cosx dx = ¼∫sin(2x) d(2x) = -¼ cos(2x) + C = -¼(1 - 2sin²x) + C = ½ sin²x + C'

Int: sinxcosx dx [remember: sin(2x) = 2sinxcosx. So, sinxcosx = .5sin(2x)]

Int: .5sin(2x) dx
Int: .25sin(u) du [let u = 2x]
.25(-cos(u)) + C
-.25cos(2x) + C