Solve for x to the nearest tenth: 5^x -18=34

Solve for x to the nearest tenth: 5^x -18=34?

5^x = 52
xln5 = ln 52
x = (ln52)/(ln5) = 2.46 = 2.5 to nearest tenth

34+18=5^x
52=5^x
x=log(sub 5)52 =>calcutate log(sub 5)52=(log(sub 10)52/log(sub 10)5)
x=2.455

Your problem is "5^x = 34 + 18; 5^x = 52.
My problem is that I have no idea how to determine "log (base 5) 52 = x"