Physics volumetric flow rate problem
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Physics volumetric flow rate problem

[From: ] [author: ] [Date: 12-04-27] [Hit: ]
00 cm/sin the wide pipe, how fast will it be flowing through the narrow one?I need to find the velocity in cm/s.Thanks!!v2 = (r1/r2)^2 v1-(2.......
You need to extend a 2.20 inch diameter pipe, but you have only a 1.00 inch diameter pipe on hand. You make a fitting to connect these pipes end to end.

If the water is flowing at 9.00 cm/s in the wide pipe, how fast will it be flowing through the narrow one?

I need to find the velocity in cm/s. Thanks!!

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"continuity equation":
flow rate in = flow rate out
A1 v1 = A2 v2

substitute pi*r^2 for each of the areas and solve for v2

v2 = (r1/r2)^2 v1

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(2.2^2 x 9)/(1^2) = 43.56cm/sec.

Or, (2.2^2/1^2) x 9 = 43.56cm/sec.
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