Ho do you solve 3^(2x+2)=10
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Ho do you solve 3^(2x+2)=10

[From: ] [author: ] [Date: 12-04-30] [Hit: ]
......
any help appreciated

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(2x+2)log3 = log10
x = 0.047952

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Natural log of both sides bring down 2x+2 divide by ln3 -2 divide by 2
Answer is x=(ln10/2ln3) -2

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3^(2x + 2) = 10
log(3^(2x + 2)) = log10
(2x + 2)log3 = 1
2x + 2 = 1/log3
x = (1/log3 - 2)/2
1
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