In a triangle, two sides that measure 6 cm and 10 cm form an angle that measures 80°. Find, to the nearest degree, the measure of the smallest angle in the triangle. Please show work if you can, thanks!!!!
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the third side is d
d² = 6² + 10² - 2*6*10cos80°
d = 10.73
small side = 6
sinA / 6 = sin80°/10.73
sinA =
A = 33.4° ==> 33° ==> answer
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d² = 6² + 10² - 2*6*10cos80°
d = 10.73
small side = 6
sinA / 6 = sin80°/10.73
sinA =
A = 33.4° ==> 33° ==> answer
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